Base | Representation |
---|---|
bin | 100000110110110100001000… |
… | …011101001110100101011011 |
3 | 200221122110220021111121002001 |
4 | 200312310020131032211123 |
5 | 122420024320014203223 |
6 | 1231200211103021431 |
7 | 42303043450211041 |
oct | 4066641035164533 |
9 | 627573807447061 |
10 | 144504316553563 |
11 | 42052a3352494a |
12 | 14259aa329a877 |
13 | 6282910a20bb5 |
14 | 2798090c46391 |
15 | 11a8d5002d9ad |
hex | 836d0874e95b |
144504316553563 has 2 divisors, whose sum is σ = 144504316553564. Its totient is φ = 144504316553562.
The previous prime is 144504316553503. The next prime is 144504316553581. The reversal of 144504316553563 is 365355613405441.
It is a strong prime.
It is an emirp because it is prime and its reverse (365355613405441) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 144504316553563 - 213 = 144504316545371 is a prime.
It is a super-2 number, since 2×1445043165535632 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (144504316553503) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72252158276781 + 72252158276782.
It is an arithmetic number, because the mean of its divisors is an integer number (72252158276782).
Almost surely, 2144504316553563 is an apocalyptic number.
144504316553563 is a deficient number, since it is larger than the sum of its proper divisors (1).
144504316553563 is an equidigital number, since it uses as much as digits as its factorization.
144504316553563 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 38880000, while the sum is 55.
The spelling of 144504316553563 in words is "one hundred forty-four trillion, five hundred four billion, three hundred sixteen million, five hundred fifty-three thousand, five hundred sixty-three".
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