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1445511231457 is a prime number
BaseRepresentation
bin10101000010001111001…
…011101111011111100001
312010012010011101220020221
4111002033023233133201
5142140401333401312
63024020402203041
7206302054511026
oct25021713573741
95105104356227
101445511231457
11508046451077
121b4196953481
13a6407703327
144dd6ab1554d
15279038d4207
hex1508f2ef7e1

1445511231457 has 2 divisors, whose sum is σ = 1445511231458. Its totient is φ = 1445511231456.

The previous prime is 1445511231431. The next prime is 1445511231503. The reversal of 1445511231457 is 7541321155441.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1387380092641 + 58131138816 = 1177871^2 + 241104^2 .

It is a cyclic number.

It is not a de Polignac number, because 1445511231457 - 215 = 1445511198689 is a prime.

It is a super-4 number, since 4×14455112314574 (a number of 50 digits) contains 4444 as substring.

It is not a weakly prime, because it can be changed into another prime (1445511231757) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 722755615728 + 722755615729.

It is an arithmetic number, because the mean of its divisors is an integer number (722755615729).

Almost surely, 21445511231457 is an apocalyptic number.

It is an amenable number.

1445511231457 is a deficient number, since it is larger than the sum of its proper divisors (1).

1445511231457 is an equidigital number, since it uses as much as digits as its factorization.

1445511231457 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 336000, while the sum is 43.

Adding to 1445511231457 its reverse (7541321155441), we get a palindrome (8986832386898).

The spelling of 1445511231457 in words is "one trillion, four hundred forty-five billion, five hundred eleven million, two hundred thirty-one thousand, four hundred fifty-seven".