1447487606113 has 2 divisors, whose sum is σ = 1447487606114. Its totient is φ = 1447487606112.

The previous prime is 1447487606077. The next prime is 1447487606203. The reversal of 1447487606113 is 3116067847441.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1160568826209 + 286918779904 = 1077297^2 + 535648^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1447487606113 is a prime.

It is not a weakly prime, because it can be changed into another prime (1447487906113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 723743803056 + 723743803057.

It is an arithmetic number, because the mean of its divisors is an integer number (723743803057).

Almost surely, 2^{1447487606113} is an apocalyptic number.

It is an amenable number.

1447487606113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1447487606113 is an equidigital number, since it uses as much as digits as its factorization.

1447487606113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2709504, while the sum is 52.

The spelling of 1447487606113 in words is "one trillion, four hundred forty-seven billion, four hundred eighty-seven million, six hundred six thousand, one hundred thirteen".