1448431140217 has 2 divisors, whose sum is σ = 1448431140218. Its totient is φ = 1448431140216.

The previous prime is 1448431140181. The next prime is 1448431140229. The reversal of 1448431140217 is 7120411348441.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1371625114896 + 76806025321 = 1171164^2 + 277139^2 .

It is an emirp because it is prime and its reverse (7120411348441) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1448431140217 - 2²³ = 1448422751609 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1448431140217.

It is not a weakly prime, because it can be changed into another prime (1448431140817) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 724215570108 + 724215570109.

It is an arithmetic number, because the mean of its divisors is an integer number (724215570109).

Almost surely, 2^{1448431140217} is an apocalyptic number.

It is an amenable number.

1448431140217 is a deficient number, since it is larger than the sum of its proper divisors (1).

1448431140217 is an equidigital number, since it uses as much as digits as its factorization.

1448431140217 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 86016, while the sum is 40.

Adding to 1448431140217 its reverse (7120411348441), we get a palindrome (8568842488658).

The spelling of 1448431140217 in words is "one trillion, four hundred forty-eight billion, four hundred thirty-one million, one hundred forty thousand, two hundred seventeen".