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14490451 is a prime number
BaseRepresentation
bin110111010001…
…101101010011
31000021012011101
4313101231103
512202143301
61234325231
7234111133
oct67215523
930235141
1014490451
1181a7988
124a29817
133004741
141cd2ac3
151413701
hexdd1b53

14490451 has 2 divisors, whose sum is σ = 14490452. Its totient is φ = 14490450.

The previous prime is 14490439. The next prime is 14490457. The reversal of 14490451 is 15409441.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14490451 - 25 = 14490419 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (14490457) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7245225 + 7245226.

It is an arithmetic number, because the mean of its divisors is an integer number (7245226).

Almost surely, 214490451 is an apocalyptic number.

14490451 is a deficient number, since it is larger than the sum of its proper divisors (1).

14490451 is an equidigital number, since it uses as much as digits as its factorization.

14490451 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2880, while the sum is 28.

The square root of 14490451 is about 3806.6325013061. The cubic root of 14490451 is about 243.7964070309.

Adding to 14490451 its reverse (15409441), we get a palindrome (29899892).

It can be divided in two parts, 14490 and 451, that added together give a palindrome (14941).

The spelling of 14490451 in words is "fourteen million, four hundred ninety thousand, four hundred fifty-one".