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144905401 is a prime number
BaseRepresentation
bin10001010001100…
…01010010111001
3101002122221211201
420220301102321
5244043433101
622213454201
73406450504
oct1050612271
9332587751
10144905401
1174882633
1240641361
1324037054
141536013b
15cac4e01
hex8a314b9

144905401 has 2 divisors, whose sum is σ = 144905402. Its totient is φ = 144905400.

The previous prime is 144905353. The next prime is 144905443. The reversal of 144905401 is 104509441.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 116122176 + 28783225 = 10776^2 + 5365^2 .

It is a cyclic number.

It is not a de Polignac number, because 144905401 - 27 = 144905273 is a prime.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 144905401.

It is not a weakly prime, because it can be changed into another prime (144905471) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72452700 + 72452701.

It is an arithmetic number, because the mean of its divisors is an integer number (72452701).

Almost surely, 2144905401 is an apocalyptic number.

It is an amenable number.

144905401 is a deficient number, since it is larger than the sum of its proper divisors (1).

144905401 is an equidigital number, since it uses as much as digits as its factorization.

144905401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2880, while the sum is 28.

The square root of 144905401 is about 12037.6659282437. The cubic root of 144905401 is about 525.2445131626.

It can be divided in two parts, 14490 and 5401, that added together give a palindrome (19891).

The spelling of 144905401 in words is "one hundred forty-four million, nine hundred five thousand, four hundred one".