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144923121453217 is a prime number
BaseRepresentation
bin100000111100111010001011…
…001011001000100010100001
3201000010111220111210211211211
4200330322023023020202201
5122443410023043000332
61232120432441310121
742345231023135302
oct4074721313104241
9630114814724754
10144923121453217
11421a4606a16728
12143070a4195341
1362b32652698a3
1427b04606b87a9
1511b4bb27c4447
hex83ce8b2c88a1

144923121453217 has 2 divisors, whose sum is σ = 144923121453218. Its totient is φ = 144923121453216.

The previous prime is 144923121453167. The next prime is 144923121453281. The reversal of 144923121453217 is 712354121329441.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 129070866796096 + 15852254657121 = 11360936^2 + 3981489^2 .

It is a cyclic number.

It is not a de Polignac number, because 144923121453217 - 215 = 144923121420449 is a prime.

It is a super-2 number, since 2×1449231214532172 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (144923121453017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72461560726608 + 72461560726609.

It is an arithmetic number, because the mean of its divisors is an integer number (72461560726609).

Almost surely, 2144923121453217 is an apocalyptic number.

It is an amenable number.

144923121453217 is a deficient number, since it is larger than the sum of its proper divisors (1).

144923121453217 is an equidigital number, since it uses as much as digits as its factorization.

144923121453217 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1451520, while the sum is 49.

The spelling of 144923121453217 in words is "one hundred forty-four trillion, nine hundred twenty-three billion, one hundred twenty-one million, four hundred fifty-three thousand, two hundred seventeen".