Base | Representation |
---|---|
bin | 100000111110000010111011… |
… | …101001110001100100100101 |
3 | 201000101222120000112202002010 |
4 | 200332002323221301210211 |
5 | 123001200022004001201 |
6 | 1232220352455104433 |
7 | 42353665001432133 |
oct | 4076027351614445 |
9 | 630358500482063 |
10 | 145001244203301 |
11 | 422247561a60a2 |
12 | 1431a267372119 |
13 | 62ba7354a4c25 |
14 | 27b4151dcc753 |
15 | 11b6c3607abd6 |
hex | 83e0bba71925 |
145001244203301 has 16 divisors (see below), whose sum is σ = 195249984890688. Its totient is φ = 95710007520000.
The previous prime is 145001244203293. The next prime is 145001244203317. The reversal of 145001244203301 is 103302442100541.
It is not a de Polignac number, because 145001244203301 - 23 = 145001244203293 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (145001244203381) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 88151026 + ... + 89780876.
It is an arithmetic number, because the mean of its divisors is an integer number (12203124055668).
Almost surely, 2145001244203301 is an apocalyptic number.
It is an amenable number.
145001244203301 is a deficient number, since it is larger than the sum of its proper divisors (50248740687387).
145001244203301 is a wasteful number, since it uses less digits than its factorization.
145001244203301 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1923572.
The product of its (nonzero) digits is 11520, while the sum is 30.
Adding to 145001244203301 its reverse (103302442100541), we get a palindrome (248303686303842).
The spelling of 145001244203301 in words is "one hundred forty-five trillion, one billion, two hundred forty-four million, two hundred three thousand, three hundred one".
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