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145003804793 is a prime number
BaseRepresentation
bin1000011100001011100…
…1100111100001111001
3111212021120020111111122
42013002321213201321
54333431433223133
6150340330435025
713322221001321
oct2070271474171
9455246214448
10145003804793
115654a95a801
1224129592a75
131089b453633
147038000281
153b8a17a498
hex21c2e67879

145003804793 has 2 divisors, whose sum is σ = 145003804794. Its totient is φ = 145003804792.

The previous prime is 145003804753. The next prime is 145003804811. The reversal of 145003804793 is 397408300541.

145003804793 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 116283046009 + 28720758784 = 341003^2 + 169472^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-145003804793 is a prime.

It is a super-2 number, since 2×1450038047932 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (145003804703) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72501902396 + 72501902397.

It is an arithmetic number, because the mean of its divisors is an integer number (72501902397).

Almost surely, 2145003804793 is an apocalyptic number.

It is an amenable number.

145003804793 is a deficient number, since it is larger than the sum of its proper divisors (1).

145003804793 is an equidigital number, since it uses as much as digits as its factorization.

145003804793 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 362880, while the sum is 44.

The spelling of 145003804793 in words is "one hundred forty-five billion, three million, eight hundred four thousand, seven hundred ninety-three".