1450101131 has 2 divisors, whose sum is σ = 1450101132. Its totient is φ = 1450101130.

The previous prime is 1450101101. The next prime is 1450101157. The reversal of 1450101131 is 1311010541.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1450101131 - 2¹⁰ = 1450100107 is a prime.

It is a super-2 number, since 2×1450101131² = 4205586580254958322, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1450101101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 725050565 + 725050566.

It is an arithmetic number, because the mean of its divisors is an integer number (725050566).

Almost surely, 2^1450101131 is an apocalyptic number.

1450101131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1450101131 is an equidigital number, since it uses as much as digits as its factorization.

1450101131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 60, while the sum is 17.

The square root of 1450101131 is about 38080.1934212525. The cubic root of 1450101131 is about 1131.8775092003.

Adding to 1450101131 its reverse (1311010541), we get a palindrome (2761111672).

The spelling of 1450101131 in words is "one billion, four hundred fifty million, one hundred one thousand, one hundred thirty-one".