Base | Representation |
---|---|
bin | 11011000000101100… |
… | …01110100000101111 |
3 | 1101102121211110110021 |
4 | 31200112032200233 |
5 | 214144320404411 |
6 | 10354542023011 |
7 | 1022233236526 |
oct | 154026164057 |
9 | 41377743407 |
10 | 14501341231 |
11 | 61716a1333 |
12 | 2988577a67 |
13 | 14a14435b0 |
14 | 9b7cdb4bd |
15 | 59d163a71 |
hex | 36058e82f |
14501341231 has 16 divisors (see below), whose sum is σ = 16821504000. Its totient is φ = 12390824160.
The previous prime is 14501341223. The next prime is 14501341237. The reversal of 14501341231 is 13214310541.
It is not a de Polignac number, because 14501341231 - 23 = 14501341223 is a prime.
It is a super-2 number, since 2×145013412312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 14501341196 and 14501341205.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14501341237) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 772981 + ... + 791518.
It is an arithmetic number, because the mean of its divisors is an integer number (1051344000).
Almost surely, 214501341231 is an apocalyptic number.
14501341231 is a deficient number, since it is larger than the sum of its proper divisors (2320162769).
14501341231 is a wasteful number, since it uses less digits than its factorization.
14501341231 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1564566.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 14501341231 its reverse (13214310541), we get a palindrome (27715651772).
The spelling of 14501341231 in words is "fourteen billion, five hundred one million, three hundred forty-one thousand, two hundred thirty-one".
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