Base | Representation |
---|---|
bin | 1000011100001110000… |
… | …0101010101011101011 |
3 | 111212022021111120101101 |
4 | 2013003200222223223 |
5 | 4333442043310243 |
6 | 150341334102231 |
7 | 13322404004404 |
oct | 2070340525353 |
9 | 455267446341 |
10 | 145014041323 |
11 | 56555711648 |
12 | 24130aaa977 |
13 | 108a05c8a58 |
14 | 70395069ab |
15 | 3b8aeed54d |
hex | 21c382aaeb |
145014041323 has 2 divisors, whose sum is σ = 145014041324. Its totient is φ = 145014041322.
The previous prime is 145014041279. The next prime is 145014041353. The reversal of 145014041323 is 323140410541.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-145014041323 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 145014041291 and 145014041300.
It is not a weakly prime, because it can be changed into another prime (145014041353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72507020661 + 72507020662.
It is an arithmetic number, because the mean of its divisors is an integer number (72507020662).
Almost surely, 2145014041323 is an apocalyptic number.
145014041323 is a deficient number, since it is larger than the sum of its proper divisors (1).
145014041323 is an equidigital number, since it uses as much as digits as its factorization.
145014041323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5760, while the sum is 28.
Adding to 145014041323 its reverse (323140410541), we get a palindrome (468154451864).
The spelling of 145014041323 in words is "one hundred forty-five billion, fourteen million, forty-one thousand, three hundred twenty-three".
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