Base | Representation |
---|---|
bin | 11011000000101101… |
… | …11101110110011011 |
3 | 1101102122012022102202 |
4 | 31200112331312123 |
5 | 214144343111011 |
6 | 10354550120415 |
7 | 1022235005036 |
oct | 154026756633 |
9 | 41378168382 |
10 | 14501535131 |
11 | 6171813a86 |
12 | 298865010b |
13 | 14a14b0925 |
14 | 9b7d4c01d |
15 | 59d1a123b |
hex | 3605bdd9b |
14501535131 has 2 divisors, whose sum is σ = 14501535132. Its totient is φ = 14501535130.
The previous prime is 14501535119. The next prime is 14501535137. The reversal of 14501535131 is 13153510541.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14501535131 - 26 = 14501535067 is a prime.
It is a super-2 number, since 2×145015351312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 14501535094 and 14501535103.
It is not a weakly prime, because it can be changed into another prime (14501535137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7250767565 + 7250767566.
It is an arithmetic number, because the mean of its divisors is an integer number (7250767566).
Almost surely, 214501535131 is an apocalyptic number.
14501535131 is a deficient number, since it is larger than the sum of its proper divisors (1).
14501535131 is an equidigital number, since it uses as much as digits as its factorization.
14501535131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4500, while the sum is 29.
The spelling of 14501535131 in words is "fourteen billion, five hundred one million, five hundred thirty-five thousand, one hundred thirty-one".
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