Base | Representation |
---|---|
bin | 1101001100001000110111… |
… | …1001011001101010111011 |
3 | 1220100101200120102200101111 |
4 | 3103002031321121222323 |
5 | 3400100441144213412 |
6 | 50502114134301151 |
7 | 3024514536010663 |
oct | 323021571315273 |
9 | 56311616380344 |
10 | 14502190226107 |
11 | 4691387347401 |
12 | 17627561b77b7 |
13 | 812720a906ac |
14 | 381ca45071a3 |
15 | 1a237de6c2a7 |
hex | d308de59abb |
14502190226107 has 2 divisors, whose sum is σ = 14502190226108. Its totient is φ = 14502190226106.
The previous prime is 14502190226033. The next prime is 14502190226179. The reversal of 14502190226107 is 70162209120541.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14502190226107 - 27 = 14502190225979 is a prime.
It is a super-3 number, since 3×145021902261073 (a number of 40 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 14502190226107.
It is not a weakly prime, because it can be changed into another prime (14502190226707) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7251095113053 + 7251095113054.
It is an arithmetic number, because the mean of its divisors is an integer number (7251095113054).
Almost surely, 214502190226107 is an apocalyptic number.
14502190226107 is a deficient number, since it is larger than the sum of its proper divisors (1).
14502190226107 is an equidigital number, since it uses as much as digits as its factorization.
14502190226107 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 60480, while the sum is 40.
Adding to 14502190226107 its reverse (70162209120541), we get a palindrome (84664399346648).
The spelling of 14502190226107 in words is "fourteen trillion, five hundred two billion, one hundred ninety million, two hundred twenty-six thousand, one hundred seven".
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