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1450351053434 = 2725175526717
BaseRepresentation
bin10101000110101111101…
…010001100101001111010
312010122121110101022212202
4111012233222030221322
5142230304332202214
63030140532310202
7206533023355133
oct25065752145172
95118543338782
101450351053434
1150a0aa3a4a48
121b5107772362
13a69c930b40a
14502a97dcc8a
1527ad874a6de
hex151afa8ca7a

1450351053434 has 4 divisors (see below), whose sum is σ = 2175526580154. Its totient is φ = 725175526716.

The previous prime is 1450351053427. The next prime is 1450351053461. The reversal of 1450351053434 is 4343501530541.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 1445878787809 + 4472265625 = 1202447^2 + 66875^2 .

It is a super-2 number, since 2×14503510534342 (a number of 25 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 362587763357 + ... + 362587763360.

Almost surely, 21450351053434 is an apocalyptic number.

1450351053434 is a deficient number, since it is larger than the sum of its proper divisors (725175526720).

1450351053434 is an equidigital number, since it uses as much as digits as its factorization.

1450351053434 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 725175526719.

The product of its (nonzero) digits is 216000, while the sum is 38.

Adding to 1450351053434 its reverse (4343501530541), we get a palindrome (5793852583975).

The spelling of 1450351053434 in words is "one trillion, four hundred fifty billion, three hundred fifty-one million, fifty-three thousand, four hundred thirty-four".

Divisors: 1 2 725175526717 1450351053434