Base | Representation |
---|---|
bin | 10001010010100… |
… | …01101011001111 |
3 | 101002220200202221 |
4 | 20221101223033 |
5 | 244112204111 |
6 | 22220400211 |
7 | 3410542255 |
oct | 1051215317 |
9 | 332820687 |
10 | 145038031 |
11 | 74963246 |
12 | 406a6067 |
13 | 24082528 |
14 | 153965d5 |
15 | caee371 |
hex | 8a51acf |
145038031 has 4 divisors (see below), whose sum is σ = 145561912. Its totient is φ = 144514152.
The previous prime is 145038017. The next prime is 145038041. The reversal of 145038031 is 130830541.
145038031 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 130830541 = 1213 ⋅107857.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-145038031 is a prime.
It is a super-2 number, since 2×1450380312 = 42072060872713922, which contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 145037987 and 145038005.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (145038041) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 261525 + ... + 262078.
It is an arithmetic number, because the mean of its divisors is an integer number (36390478).
Almost surely, 2145038031 is an apocalyptic number.
145038031 is a deficient number, since it is larger than the sum of its proper divisors (523881).
145038031 is an equidigital number, since it uses as much as digits as its factorization.
145038031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 523880.
The product of its (nonzero) digits is 1440, while the sum is 25.
The square root of 145038031 is about 12043.1736265820. The cubic root of 145038031 is about 525.4047140849.
Adding to 145038031 its reverse (130830541), we get a palindrome (275868572).
The spelling of 145038031 in words is "one hundred forty-five million, thirty-eight thousand, thirty-one".
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