Base | Representation |
---|---|
bin | 1000011100010100001… |
… | …1111000011111100011 |
3 | 111212101002102221210011 |
4 | 2013011003320133203 |
5 | 4334020223101042 |
6 | 150344103345351 |
7 | 13323141041026 |
oct | 2070503703743 |
9 | 455332387704 |
10 | 145040050147 |
11 | 56569366443 |
12 | 24139752257 |
13 | 108a5b041a5 |
14 | 703cb571bd |
15 | 3b8d439a17 |
hex | 21c50f87e3 |
145040050147 has 2 divisors, whose sum is σ = 145040050148. Its totient is φ = 145040050146.
The previous prime is 145040050139. The next prime is 145040050157. The reversal of 145040050147 is 741050040541.
145040050147 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 145040050147 - 23 = 145040050139 is a prime.
It is a super-2 number, since 2×1450400501472 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (145040050157) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72520025073 + 72520025074.
It is an arithmetic number, because the mean of its divisors is an integer number (72520025074).
Almost surely, 2145040050147 is an apocalyptic number.
145040050147 is a deficient number, since it is larger than the sum of its proper divisors (1).
145040050147 is an equidigital number, since it uses as much as digits as its factorization.
145040050147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11200, while the sum is 31.
Adding to 145040050147 its reverse (741050040541), we get a palindrome (886090090688).
The spelling of 145040050147 in words is "one hundred forty-five billion, forty million, fifty thousand, one hundred forty-seven".
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