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145042650451 is a prime number
BaseRepresentation
bin1000011100010100110…
…1110011010101010011
3111212101021100001201201
42013011031303111103
54334021404303301
6150344235212031
713323202121056
oct2070515632523
9455337301651
10145042650451
115656a882056
122413a5a7017
13108a650492a
14703d232a9d
153b8d7a0201
hex21c5373553

145042650451 has 2 divisors, whose sum is σ = 145042650452. Its totient is φ = 145042650450.

The previous prime is 145042650391. The next prime is 145042650469. The reversal of 145042650451 is 154056240541.

145042650451 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 145042650451 - 27 = 145042650323 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 145042650451.

It is not a weakly prime, because it can be changed into another prime (145042650491) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72521325225 + 72521325226.

It is an arithmetic number, because the mean of its divisors is an integer number (72521325226).

Almost surely, 2145042650451 is an apocalyptic number.

145042650451 is a deficient number, since it is larger than the sum of its proper divisors (1).

145042650451 is an equidigital number, since it uses as much as digits as its factorization.

145042650451 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96000, while the sum is 37.

Adding to 145042650451 its reverse (154056240541), we get a palindrome (299098890992).

The spelling of 145042650451 in words is "one hundred forty-five billion, forty-two million, six hundred fifty thousand, four hundred fifty-one".