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14505540555137 is a prime number
BaseRepresentation
bin1101001100010101010110…
…0101111001000110000001
31220100201100001200000210212
43103011111211321012001
53400124321340231022
650503430415403505
73024663550231052
oct323052545710601
956321301600725
1014505540555137
114692846537175
121763330223595
13812b35c14ac8
14382101464729
151a24c81623e2
hexd3155979181

14505540555137 has 2 divisors, whose sum is σ = 14505540555138. Its totient is φ = 14505540555136.

The previous prime is 14505540555101. The next prime is 14505540555169. The reversal of 14505540555137 is 73155504550541.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14440638407056 + 64902148081 = 3800084^2 + 254759^2 .

It is a cyclic number.

It is not a de Polignac number, because 14505540555137 - 220 = 14505539506561 is a prime.

It is a super-2 number, since 2×145055405551372 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14505540554137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7252770277568 + 7252770277569.

It is an arithmetic number, because the mean of its divisors is an integer number (7252770277569).

Almost surely, 214505540555137 is an apocalyptic number.

It is an amenable number.

14505540555137 is a deficient number, since it is larger than the sum of its proper divisors (1).

14505540555137 is an equidigital number, since it uses as much as digits as its factorization.

14505540555137 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5250000, while the sum is 50.

The spelling of 14505540555137 in words is "fourteen trillion, five hundred five billion, five hundred forty million, five hundred fifty-five thousand, one hundred thirty-seven".