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1450605503233 is a prime number
BaseRepresentation
bin10101000110111110110…
…100110110001100000001
312010200021012011201101101
4111012332310312030001
5142231320002100413
63030222102134401
7206542233222235
oct25067664661401
95120235151341
101450605503233
1150a21aa97937
121b5178a21401
13a6a39c4b323
14502d15165c5
1527b00c5cedd
hex151bed36301

1450605503233 has 2 divisors, whose sum is σ = 1450605503234. Its totient is φ = 1450605503232.

The previous prime is 1450605503131. The next prime is 1450605503251. The reversal of 1450605503233 is 3323055060541.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1177904307969 + 272701195264 = 1085313^2 + 522208^2 .

It is an emirp because it is prime and its reverse (3323055060541) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1450605503233 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1450605503192 and 1450605503201.

It is not a weakly prime, because it can be changed into another prime (1450605503833) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 725302751616 + 725302751617.

It is an arithmetic number, because the mean of its divisors is an integer number (725302751617).

Almost surely, 21450605503233 is an apocalyptic number.

It is an amenable number.

1450605503233 is a deficient number, since it is larger than the sum of its proper divisors (1).

1450605503233 is an equidigital number, since it uses as much as digits as its factorization.

1450605503233 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 162000, while the sum is 37.

The spelling of 1450605503233 in words is "one trillion, four hundred fifty billion, six hundred five million, five hundred three thousand, two hundred thirty-three".