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14511100056415 = 52902220011283
BaseRepresentation
bin1101001100101010000011…
…1101101101001101011111
31220101020200111211221211121
43103022200331231031133
53400222213103301130
650510150215031411
73025251405221434
oct323124075551537
956336614757747
1014511100056415
114695139750826
12176442206b567
1381351095c731
143824ab969b8b
151a2701286d7a
hexd32a0f6d35f

14511100056415 has 4 divisors (see below), whose sum is σ = 17413320067704. Its totient is φ = 11608880045128.

The previous prime is 14511100056391. The next prime is 14511100056421. The reversal of 14511100056415 is 51465000111541.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14511100056415 - 27 = 14511100056287 is a prime.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1451110005637 + ... + 1451110005646.

It is an arithmetic number, because the mean of its divisors is an integer number (4353330016926).

Almost surely, 214511100056415 is an apocalyptic number.

14511100056415 is a deficient number, since it is larger than the sum of its proper divisors (2902220011289).

14511100056415 is an equidigital number, since it uses as much as digits as its factorization.

14511100056415 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2902220011288.

The product of its (nonzero) digits is 12000, while the sum is 34.

Adding to 14511100056415 its reverse (51465000111541), we get a palindrome (65976100167956).

The spelling of 14511100056415 in words is "fourteen trillion, five hundred eleven billion, one hundred million, fifty-six thousand, four hundred fifteen".

Divisors: 1 5 2902220011283 14511100056415