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145121113 is a prime number
BaseRepresentation
bin10001010011001…
…01111101011001
3101010001220202001
420221211331121
5244122333423
622222241001
73411336424
oct1051457531
9333056661
10145121113
1174a0a705
1240726161
13240b12a7
14153b89bb
15cb18cad
hex8a65f59

145121113 has 2 divisors, whose sum is σ = 145121114. Its totient is φ = 145121112.

The previous prime is 145121071. The next prime is 145121147. The reversal of 145121113 is 311121541.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 143712144 + 1408969 = 11988^2 + 1187^2 .

It is a cyclic number.

It is not a de Polignac number, because 145121113 - 29 = 145120601 is a prime.

It is not a weakly prime, because it can be changed into another prime (145121813) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72560556 + 72560557.

It is an arithmetic number, because the mean of its divisors is an integer number (72560557).

Almost surely, 2145121113 is an apocalyptic number.

It is an amenable number.

145121113 is a deficient number, since it is larger than the sum of its proper divisors (1).

145121113 is an equidigital number, since it uses as much as digits as its factorization.

145121113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 120, while the sum is 19.

The square root of 145121113 is about 12046.6224727099. The cubic root of 145121113 is about 525.5050172992.

Adding to 145121113 its reverse (311121541), we get a palindrome (456242654).

It can be divided in two parts, 14512 and 1113, that added together give a 6-th power (15625 = 56).

The spelling of 145121113 in words is "one hundred forty-five million, one hundred twenty-one thousand, one hundred thirteen".