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145125505673 is a prime number
BaseRepresentation
bin1000011100101000100…
…1110111101010001001
3111212121001020112201122
42013022021313222021
54334204112140143
6150400355125025
713325226305351
oct2071211675211
9455531215648
10145125505673
1156602623445
12241622a3775
13108ba7247a5
14704a23db61
153b95bb9c68
hex21ca277a89

145125505673 has 2 divisors, whose sum is σ = 145125505674. Its totient is φ = 145125505672.

The previous prime is 145125505669. The next prime is 145125505691. The reversal of 145125505673 is 376505521541.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 143434897984 + 1690607689 = 378728^2 + 41117^2 .

It is a cyclic number.

It is not a de Polignac number, because 145125505673 - 22 = 145125505669 is a prime.

It is a super-2 number, since 2×1451255056732 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (145125501673) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72562752836 + 72562752837.

It is an arithmetic number, because the mean of its divisors is an integer number (72562752837).

Almost surely, 2145125505673 is an apocalyptic number.

It is an amenable number.

145125505673 is a deficient number, since it is larger than the sum of its proper divisors (1).

145125505673 is an equidigital number, since it uses as much as digits as its factorization.

145125505673 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 630000, while the sum is 44.

The spelling of 145125505673 in words is "one hundred forty-five billion, one hundred twenty-five million, five hundred five thousand, six hundred seventy-three".