Base | Representation |
---|---|
bin | 11011000010000101… |
… | …11001001000111011 |
3 | 1101110102212100002201 |
4 | 31201002321020323 |
5 | 214210320101141 |
6 | 10400041011031 |
7 | 1022434614424 |
oct | 154102711073 |
9 | 41412770081 |
10 | 14513050171 |
11 | 6178269444 |
12 | 2990483a77 |
13 | 14a39b2c69 |
14 | 9b96a864b |
15 | 59e1c8031 |
hex | 3610b923b |
14513050171 has 2 divisors, whose sum is σ = 14513050172. Its totient is φ = 14513050170.
The previous prime is 14513050121. The next prime is 14513050213. The reversal of 14513050171 is 17105031541.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14513050171 - 27 = 14513050043 is a prime.
It is a super-3 number, since 3×145130501713 (a number of 31 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (14513050121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7256525085 + 7256525086.
It is an arithmetic number, because the mean of its divisors is an integer number (7256525086).
Almost surely, 214513050171 is an apocalyptic number.
14513050171 is a deficient number, since it is larger than the sum of its proper divisors (1).
14513050171 is an equidigital number, since it uses as much as digits as its factorization.
14513050171 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2100, while the sum is 28.
The spelling of 14513050171 in words is "fourteen billion, five hundred thirteen million, fifty thousand, one hundred seventy-one".
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