Base | Representation |
---|---|
bin | 1101001100110001100000… |
… | …1011000010101101001011 |
3 | 1220101102211220011200222001 |
4 | 3103030120023002231023 |
5 | 3400240312102303120 |
6 | 50511120501411431 |
7 | 3025352101630411 |
oct | 323143013025513 |
9 | 56342756150861 |
10 | 14513100041035 |
11 | 4695a75687882 |
12 | 176489ba09b77 |
13 | 81376c0cca9b |
14 | 38261b41d2b1 |
15 | 1a27bbb44e0a |
hex | d33182c2b4b |
14513100041035 has 32 divisors (see below), whose sum is σ = 17942053248000. Its totient is φ = 11261582513280.
The previous prime is 14513100040991. The next prime is 14513100041051. The reversal of 14513100041035 is 53014000131541.
It is not a de Polignac number, because 14513100041035 - 225 = 14513066486603 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14513100040994 and 14513100041012.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 108376570 + ... + 108510400.
It is an arithmetic number, because the mean of its divisors is an integer number (560689164000).
Almost surely, 214513100041035 is an apocalyptic number.
14513100041035 is a deficient number, since it is larger than the sum of its proper divisors (3428953206965).
14513100041035 is a wasteful number, since it uses less digits than its factorization.
14513100041035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 135691.
The product of its (nonzero) digits is 3600, while the sum is 28.
Adding to 14513100041035 its reverse (53014000131541), we get a palindrome (67527100172576).
The spelling of 14513100041035 in words is "fourteen trillion, five hundred thirteen billion, one hundred million, forty-one thousand, thirty-five".
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