Base | Representation |
---|---|
bin | 1000011100101010010… |
… | …0010101011000001111 |
3 | 111212121112022000011021 |
4 | 2013022210111120033 |
5 | 4334212401140101 |
6 | 150401203535011 |
7 | 13325342261263 |
oct | 2071244253017 |
9 | 455545260137 |
10 | 145132443151 |
11 | 566065316a3 |
12 | 2416468a467 |
13 | 108bbcb33c7 |
14 | 704b1280a3 |
15 | 3b965da5a1 |
hex | 21ca91560f |
145132443151 has 4 divisors (see below), whose sum is σ = 145596125392. Its totient is φ = 144668760912.
The previous prime is 145132443149. The next prime is 145132443173. The reversal of 145132443151 is 151344231541.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 145132443151 - 21 = 145132443149 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (145132443101) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 231840651 + ... + 231841276.
It is an arithmetic number, because the mean of its divisors is an integer number (36399031348).
Almost surely, 2145132443151 is an apocalyptic number.
145132443151 is a deficient number, since it is larger than the sum of its proper divisors (463682241).
145132443151 is an equidigital number, since it uses as much as digits as its factorization.
145132443151 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 463682240.
The product of its digits is 28800, while the sum is 34.
Adding to 145132443151 its reverse (151344231541), we get a palindrome (296476674692).
The spelling of 145132443151 in words is "one hundred forty-five billion, one hundred thirty-two million, four hundred forty-three thousand, one hundred fifty-one".
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