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145132443151 = 313463681927
BaseRepresentation
bin1000011100101010010…
…0010101011000001111
3111212121112022000011021
42013022210111120033
54334212401140101
6150401203535011
713325342261263
oct2071244253017
9455545260137
10145132443151
11566065316a3
122416468a467
13108bbcb33c7
14704b1280a3
153b965da5a1
hex21ca91560f

145132443151 has 4 divisors (see below), whose sum is σ = 145596125392. Its totient is φ = 144668760912.

The previous prime is 145132443149. The next prime is 145132443173. The reversal of 145132443151 is 151344231541.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 145132443151 - 21 = 145132443149 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (145132443101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 231840651 + ... + 231841276.

It is an arithmetic number, because the mean of its divisors is an integer number (36399031348).

Almost surely, 2145132443151 is an apocalyptic number.

145132443151 is a deficient number, since it is larger than the sum of its proper divisors (463682241).

145132443151 is an equidigital number, since it uses as much as digits as its factorization.

145132443151 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 463682240.

The product of its digits is 28800, while the sum is 34.

Adding to 145132443151 its reverse (151344231541), we get a palindrome (296476674692).

The spelling of 145132443151 in words is "one hundred forty-five billion, one hundred thirty-two million, four hundred forty-three thousand, one hundred fifty-one".

Divisors: 1 313 463681927 145132443151