Base | Representation |
---|---|
bin | 100000111111111101110110… |
… | …111100010001110000111011 |
3 | 201000212121020201021212120021 |
4 | 200333331312330101300323 |
5 | 123010330331231141102 |
6 | 1232401142104511311 |
7 | 42366346604254552 |
oct | 4077756674216073 |
9 | 630777221255507 |
10 | 145133235412027 |
11 | 42275728857875 |
12 | 1433b962a7b537 |
13 | 62ca00ba66475 |
14 | 27ba6b3b04d99 |
15 | 11ba3adb17137 |
hex | 83ff76f11c3b |
145133235412027 has 2 divisors, whose sum is σ = 145133235412028. Its totient is φ = 145133235412026.
The previous prime is 145133235411973. The next prime is 145133235412057. The reversal of 145133235412027 is 720214532331541.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 145133235412027 - 211 = 145133235409979 is a prime.
It is not a weakly prime, because it can be changed into another prime (145133235412057) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72566617706013 + 72566617706014.
It is an arithmetic number, because the mean of its divisors is an integer number (72566617706014).
Almost surely, 2145133235412027 is an apocalyptic number.
145133235412027 is a deficient number, since it is larger than the sum of its proper divisors (1).
145133235412027 is an equidigital number, since it uses as much as digits as its factorization.
145133235412027 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 604800, while the sum is 43.
Adding to 145133235412027 its reverse (720214532331541), we get a palindrome (865347767743568).
The spelling of 145133235412027 in words is "one hundred forty-five trillion, one hundred thirty-three billion, two hundred thirty-five million, four hundred twelve thousand, twenty-seven".
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