Base | Representation |
---|---|
bin | 1101001100110010010111… |
… | …1100111001000001110011 |
3 | 1220101110110000011102110120 |
4 | 3103030211330321001303 |
5 | 3400241300242244103 |
6 | 50511155440301323 |
7 | 3025360606562412 |
oct | 323144574710163 |
9 | 56343400142416 |
10 | 14513331212403 |
11 | 46960841202a1 |
12 | 1764945311843 |
13 | 8137a7c7c28a |
14 | 38263ddd7479 |
15 | 1a27d20aa253 |
hex | d3325f39073 |
14513331212403 has 64 divisors (see below), whose sum is σ = 20295817850880. Its totient is φ = 9217154314368.
The previous prime is 14513331212399. The next prime is 14513331212459. The reversal of 14513331212403 is 30421213331541.
It is not a de Polignac number, because 14513331212403 - 22 = 14513331212399 is a prime.
It is a super-2 number, since 2×145133312124032 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (14513331212483) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 816126250 + ... + 816144032.
It is an arithmetic number, because the mean of its divisors is an integer number (317122153920).
Almost surely, 214513331212403 is an apocalyptic number.
14513331212403 is a deficient number, since it is larger than the sum of its proper divisors (5782486638477).
14513331212403 is a wasteful number, since it uses less digits than its factorization.
14513331212403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 18728.
The product of its (nonzero) digits is 25920, while the sum is 33.
Adding to 14513331212403 its reverse (30421213331541), we get a palindrome (44934544543944).
The spelling of 14513331212403 in words is "fourteen trillion, five hundred thirteen billion, three hundred thirty-one million, two hundred twelve thousand, four hundred three".
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