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14513430356401 is a prime number
BaseRepresentation
bin1101001100110010101111…
…0111000110000110110001
31220101110200220201110110111
43103030223313012012301
53400242001132401101
650511213341301321
73025363222361104
oct323145367060661
956343626643414
1014513430356401
114696125087689
121764972564841
138137c2683272
1438264d24473b
151a27dab41251
hexd332bdc61b1

14513430356401 has 2 divisors, whose sum is σ = 14513430356402. Its totient is φ = 14513430356400.

The previous prime is 14513430356393. The next prime is 14513430356413. The reversal of 14513430356401 is 10465303431541.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9398663644176 + 5114766712225 = 3065724^2 + 2261585^2 .

It is a cyclic number.

It is not a de Polignac number, because 14513430356401 - 23 = 14513430356393 is a prime.

It is not a weakly prime, because it can be changed into another prime (14513430356441) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7256715178200 + 7256715178201.

It is an arithmetic number, because the mean of its divisors is an integer number (7256715178201).

Almost surely, 214513430356401 is an apocalyptic number.

It is an amenable number.

14513430356401 is a deficient number, since it is larger than the sum of its proper divisors (1).

14513430356401 is an equidigital number, since it uses as much as digits as its factorization.

14513430356401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 259200, while the sum is 40.

Adding to 14513430356401 its reverse (10465303431541), we get a palindrome (24978733787942).

The spelling of 14513430356401 in words is "fourteen trillion, five hundred thirteen billion, four hundred thirty million, three hundred fifty-six thousand, four hundred one".