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14515112130052 = 2222396311689601
BaseRepresentation
bin1101001100111001000000…
…0110100011011000000100
31220101122001010021102012111
43103032100012203120010
53400303422201130202
650512052255430404
73025453003252222
oct323162006433004
956348033242174
1014515112130052
114696908431066
121765161825404
138139ccc1a7c1
1438276c743b12
151a28885e46d7
hexd33901a3604

14515112130052 has 24 divisors (see below), whose sum is σ = 25518018455552. Its totient is φ = 7224256512000.

The previous prime is 14515112130023. The next prime is 14515112130061. The reversal of 14515112130052 is 25003121151541.

It is a super-4 number, since 4×145151121300524 (a number of 54 digits) contains 4444 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14515112129996 and 14515112130023.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7746052 + ... + 9435652.

Almost surely, 214515112130052 is an apocalyptic number.

It is an amenable number.

14515112130052 is a deficient number, since it is larger than the sum of its proper divisors (11002906325500).

14515112130052 is a wasteful number, since it uses less digits than its factorization.

14515112130052 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1699459 (or 1699457 counting only the distinct ones).

The product of its (nonzero) digits is 6000, while the sum is 31.

Adding to 14515112130052 its reverse (25003121151541), we get a palindrome (39518233281593).

The spelling of 14515112130052 in words is "fourteen trillion, five hundred fifteen billion, one hundred twelve million, one hundred thirty thousand, fifty-two".

Divisors: 1 2 4 223 446 892 9631 19262 38524 1689601 2147713 3379202 4295426 6758404 8590852 376781023 753562046 1507124092 16272547231 32545094462 65090188924 3628778032513 7257556065026 14515112130052