Base | Representation |
---|---|
bin | 1101001100111001000000… |
… | …0110100011011000000100 |
3 | 1220101122001010021102012111 |
4 | 3103032100012203120010 |
5 | 3400303422201130202 |
6 | 50512052255430404 |
7 | 3025453003252222 |
oct | 323162006433004 |
9 | 56348033242174 |
10 | 14515112130052 |
11 | 4696908431066 |
12 | 1765161825404 |
13 | 8139ccc1a7c1 |
14 | 38276c743b12 |
15 | 1a28885e46d7 |
hex | d33901a3604 |
14515112130052 has 24 divisors (see below), whose sum is σ = 25518018455552. Its totient is φ = 7224256512000.
The previous prime is 14515112130023. The next prime is 14515112130061. The reversal of 14515112130052 is 25003121151541.
It is a super-4 number, since 4×145151121300524 (a number of 54 digits) contains 4444 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 14515112129996 and 14515112130023.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7746052 + ... + 9435652.
Almost surely, 214515112130052 is an apocalyptic number.
It is an amenable number.
14515112130052 is a deficient number, since it is larger than the sum of its proper divisors (11002906325500).
14515112130052 is a wasteful number, since it uses less digits than its factorization.
14515112130052 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1699459 (or 1699457 counting only the distinct ones).
The product of its (nonzero) digits is 6000, while the sum is 31.
Adding to 14515112130052 its reverse (25003121151541), we get a palindrome (39518233281593).
The spelling of 14515112130052 in words is "fourteen trillion, five hundred fifteen billion, one hundred twelve million, one hundred thirty thousand, fifty-two".
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