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145153233111 = 348384411037
BaseRepresentation
bin1000011100101111001…
…1101001000011010111
3111212122222102020121210
42013023303221003113
54334233211424421
6150403225312503
713326014060355
oct2071363510327
9455588366553
10145153233111
1156617241487
122416b635733
13108c33b2263
14704dbba7d5
153b98345576
hex21cbce90d7

145153233111 has 4 divisors (see below), whose sum is σ = 193537644152. Its totient is φ = 96768822072.

The previous prime is 145153233103. The next prime is 145153233193. The reversal of 145153233111 is 111332351541.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 145153233111 - 23 = 145153233103 is a prime.

It is a super-2 number, since 2×1451532331112 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (145153233101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24192205516 + ... + 24192205521.

It is an arithmetic number, because the mean of its divisors is an integer number (48384411038).

Almost surely, 2145153233111 is an apocalyptic number.

145153233111 is a deficient number, since it is larger than the sum of its proper divisors (48384411041).

145153233111 is an equidigital number, since it uses as much as digits as its factorization.

145153233111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 48384411040.

The product of its digits is 5400, while the sum is 30.

Adding to 145153233111 its reverse (111332351541), we get a palindrome (256485584652).

The spelling of 145153233111 in words is "one hundred forty-five billion, one hundred fifty-three million, two hundred thirty-three thousand, one hundred eleven".

Divisors: 1 3 48384411037 145153233111