Base | Representation |
---|---|
bin | 1000011100110001110… |
… | …1111111110001110001 |
3 | 111212200202022100020211 |
4 | 2013030131333301301 |
5 | 4334244032224431 |
6 | 150404303304121 |
7 | 13326210333121 |
oct | 2071435776161 |
9 | 455622270224 |
10 | 145164336241 |
11 | 56622535421 |
12 | 241732ab041 |
13 | 108c579bc62 |
14 | 705146ac81 |
15 | 3b992da2b1 |
hex | 21cc77fc71 |
145164336241 has 2 divisors, whose sum is σ = 145164336242. Its totient is φ = 145164336240.
The previous prime is 145164336221. The next prime is 145164336269. The reversal of 145164336241 is 142633461541.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 95169165025 + 49995171216 = 308495^2 + 223596^2 .
It is a cyclic number.
It is not a de Polignac number, because 145164336241 - 223 = 145155947633 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 145164336194 and 145164336203.
It is not a weakly prime, because it can be changed into another prime (145164336221) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72582168120 + 72582168121.
It is an arithmetic number, because the mean of its divisors is an integer number (72582168121).
Almost surely, 2145164336241 is an apocalyptic number.
It is an amenable number.
145164336241 is a deficient number, since it is larger than the sum of its proper divisors (1).
145164336241 is an equidigital number, since it uses as much as digits as its factorization.
145164336241 is an evil number, because the sum of its binary digits is even.
The product of its digits is 207360, while the sum is 40.
Adding to 145164336241 its reverse (142633461541), we get a palindrome (287797797782).
The spelling of 145164336241 in words is "one hundred forty-five billion, one hundred sixty-four million, three hundred thirty-six thousand, two hundred forty-one".
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