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145201451 is a prime number
BaseRepresentation
bin10001010011110…
…01100100101011
3101010012222221112
420221321210223
5244132421301
622224100535
73412122563
oct1051714453
9333188845
10145201451
1174a64aaa
124076474b
132410ba25
14153d9da3
15cb329bb
hex8a7992b

145201451 has 2 divisors, whose sum is σ = 145201452. Its totient is φ = 145201450.

The previous prime is 145201429. The next prime is 145201457. The reversal of 145201451 is 154102541.

145201451 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (154102541) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 145201451 - 214 = 145185067 is a prime.

It is a super-2 number, since 2×1452014512 = 42166922745010802, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (145201457) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72600725 + 72600726.

It is an arithmetic number, because the mean of its divisors is an integer number (72600726).

Almost surely, 2145201451 is an apocalyptic number.

145201451 is a deficient number, since it is larger than the sum of its proper divisors (1).

145201451 is an equidigital number, since it uses as much as digits as its factorization.

145201451 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 800, while the sum is 23.

The square root of 145201451 is about 12049.9564729504. The cubic root of 145201451 is about 525.6019713378.

Adding to 145201451 its reverse (154102541), we get a palindrome (299303992).

The spelling of 145201451 in words is "one hundred forty-five million, two hundred one thousand, four hundred fifty-one".