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145212131 is a prime number
BaseRepresentation
bin10001010011111…
…00001011100011
3101010020112121002
420221330023203
5244133242011
622224222215
73412165661
oct1051741343
9333215532
10145212131
1174a72029
124076a96b
132411384c
14153ddc31
15cb35c3b
hex8a7c2e3

145212131 has 2 divisors, whose sum is σ = 145212132. Its totient is φ = 145212130.

The previous prime is 145212097. The next prime is 145212149. The reversal of 145212131 is 131212541.

145212131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 145212131 - 222 = 141017827 is a prime.

It is a super-2 number, since 2×1452121312 = 42173125979122322, which contains 22 as substring.

It is a Sophie Germain prime.

It is not a weakly prime, because it can be changed into another prime (145292131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72606065 + 72606066.

It is an arithmetic number, because the mean of its divisors is an integer number (72606066).

Almost surely, 2145212131 is an apocalyptic number.

145212131 is a deficient number, since it is larger than the sum of its proper divisors (1).

145212131 is an equidigital number, since it uses as much as digits as its factorization.

145212131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 240, while the sum is 20.

The square root of 145212131 is about 12050.3996199296. The cubic root of 145212131 is about 525.6148575530.

Adding to 145212131 its reverse (131212541), we get a palindrome (276424672).

The spelling of 145212131 in words is "one hundred forty-five million, two hundred twelve thousand, one hundred thirty-one".