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145214713537 is a prime number
BaseRepresentation
bin1000011100111101111…
…0001010111011000001
3111212211021002202220121
42013033132022323001
54334344431313122
6150413303140241
713330361461525
oct2071736127301
9455737082817
10145214713537
1156648a13653
1224188144681
1310903059cca
147058021d85
153b9d93bbc7
hex21cf78aec1

145214713537 has 2 divisors, whose sum is σ = 145214713538. Its totient is φ = 145214713536.

The previous prime is 145214713481. The next prime is 145214713571. The reversal of 145214713537 is 735317412541.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 138634096896 + 6580616641 = 372336^2 + 81121^2 .

It is an emirp because it is prime and its reverse (735317412541) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 145214713537 - 215 = 145214680769 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 145214713493 and 145214713502.

It is not a weakly prime, because it can be changed into another prime (145214719537) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72607356768 + 72607356769.

It is an arithmetic number, because the mean of its divisors is an integer number (72607356769).

Almost surely, 2145214713537 is an apocalyptic number.

It is an amenable number.

145214713537 is a deficient number, since it is larger than the sum of its proper divisors (1).

145214713537 is an equidigital number, since it uses as much as digits as its factorization.

145214713537 is an evil number, because the sum of its binary digits is even.

The product of its digits is 352800, while the sum is 43.

The spelling of 145214713537 in words is "one hundred forty-five billion, two hundred fourteen million, seven hundred thirteen thousand, five hundred thirty-seven".