Base | Representation |
---|---|
bin | 1000011101000001100… |
… | …1010011000011100011 |
3 | 111212212100021020122122 |
4 | 2013100121103003203 |
5 | 4334412413311342 |
6 | 150415015254455 |
7 | 13330640305502 |
oct | 2072031230343 |
9 | 455770236578 |
10 | 145230213347 |
11 | 5665673a90a |
12 | 2419137a42b |
13 | 10906325cab |
14 | 705a0d8839 |
15 | 3b9ee9e4d2 |
hex | 21d06530e3 |
145230213347 has 2 divisors, whose sum is σ = 145230213348. Its totient is φ = 145230213346.
The previous prime is 145230213307. The next prime is 145230213367. The reversal of 145230213347 is 743312032541.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 145230213347 - 212 = 145230209251 is a prime.
It is not a weakly prime, because it can be changed into another prime (145230213307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72615106673 + 72615106674.
It is an arithmetic number, because the mean of its divisors is an integer number (72615106674).
Almost surely, 2145230213347 is an apocalyptic number.
145230213347 is a deficient number, since it is larger than the sum of its proper divisors (1).
145230213347 is an equidigital number, since it uses as much as digits as its factorization.
145230213347 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 60480, while the sum is 35.
Adding to 145230213347 its reverse (743312032541), we get a palindrome (888542245888).
The spelling of 145230213347 in words is "one hundred forty-five billion, two hundred thirty million, two hundred thirteen thousand, three hundred forty-seven".
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