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145232413483 is a prime number
BaseRepresentation
bin1000011101000010000…
…1101100001100101011
3111212212111102000200011
42013100201230030223
54334413444212413
6150415134352351
713330665101053
oct2072041541453
9455774360604
10145232413483
1156657a02903
122419205b6b7
1310906916551
14705a50c563
153ba028633d
hex21d086c32b

145232413483 has 2 divisors, whose sum is σ = 145232413484. Its totient is φ = 145232413482.

The previous prime is 145232413463. The next prime is 145232413489. The reversal of 145232413483 is 384314232541.

It is a strong prime.

It is an emirp because it is prime and its reverse (384314232541) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-145232413483 is a prime.

It is not a weakly prime, because it can be changed into another prime (145232413489) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72616206741 + 72616206742.

It is an arithmetic number, because the mean of its divisors is an integer number (72616206742).

Almost surely, 2145232413483 is an apocalyptic number.

145232413483 is a deficient number, since it is larger than the sum of its proper divisors (1).

145232413483 is an equidigital number, since it uses as much as digits as its factorization.

145232413483 is an evil number, because the sum of its binary digits is even.

The product of its digits is 276480, while the sum is 40.

The spelling of 145232413483 in words is "one hundred forty-five billion, two hundred thirty-two million, four hundred thirteen thousand, four hundred eighty-three".