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1452334130053 = 10131433696081
BaseRepresentation
bin10101001000100101110…
…111000010001110000101
312010211201122220001120221
4111020211313002032011
5142243340014130203
63031105412424341
7206633123263462
oct25104567021605
95124648801527
101452334130053
1150aa27832844
121b557b9180b1
13a6c5410b831
1450416d30669
1527ba28b8abd
hex15225dc2385

1452334130053 has 4 divisors (see below), whose sum is σ = 1453767827148. Its totient is φ = 1450900432960.

The previous prime is 1452334130017. The next prime is 1452334130057. The reversal of 1452334130053 is 3500314332541.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 21686096644 + 1430648033409 = 147262^2 + 1196097^2 .

It is a cyclic number.

It is not a de Polignac number, because 1452334130053 - 29 = 1452334129541 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1452334130057) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 716847028 + ... + 716849053.

It is an arithmetic number, because the mean of its divisors is an integer number (363441956787).

Almost surely, 21452334130053 is an apocalyptic number.

It is an amenable number.

1452334130053 is a deficient number, since it is larger than the sum of its proper divisors (1433697095).

1452334130053 is a wasteful number, since it uses less digits than its factorization.

1452334130053 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1433697094.

The product of its (nonzero) digits is 64800, while the sum is 34.

Adding to 1452334130053 its reverse (3500314332541), we get a palindrome (4952648462594).

The spelling of 1452334130053 in words is "one trillion, four hundred fifty-two billion, three hundred thirty-four million, one hundred thirty thousand, fifty-three".

Divisors: 1 1013 1433696081 1452334130053