Base | Representation |
---|---|
bin | 100001000001011011110011… |
… | …001001010001001101110011 |
3 | 201001020020121101021121200011 |
4 | 201001123303021101031303 |
5 | 123014003420440041433 |
6 | 1232515343120435351 |
7 | 42406550321331556 |
oct | 4101336311211563 |
9 | 631206541247604 |
10 | 145234103440243 |
11 | 4230448a168364 |
12 | 14357413478b57 |
13 | 6306695356c6c |
14 | 27c152215c69d |
15 | 11bcd141653cd |
hex | 8416f3251373 |
145234103440243 has 2 divisors, whose sum is σ = 145234103440244. Its totient is φ = 145234103440242.
The previous prime is 145234103440229. The next prime is 145234103440247. The reversal of 145234103440243 is 342044301432541.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 145234103440243 - 245 = 110049731351411 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 145234103440196 and 145234103440205.
It is not a weakly prime, because it can be changed into another prime (145234103440247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72617051720121 + 72617051720122.
It is an arithmetic number, because the mean of its divisors is an integer number (72617051720122).
Almost surely, 2145234103440243 is an apocalyptic number.
145234103440243 is a deficient number, since it is larger than the sum of its proper divisors (1).
145234103440243 is an equidigital number, since it uses as much as digits as its factorization.
145234103440243 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 552960, while the sum is 40.
Adding to 145234103440243 its reverse (342044301432541), we get a palindrome (487278404872784).
The spelling of 145234103440243 in words is "one hundred forty-five trillion, two hundred thirty-four billion, one hundred three million, four hundred forty thousand, two hundred forty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •