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14524000153 = 131117230781
BaseRepresentation
bin11011000011011001…
…01010011110011001
31101111012110122122121
431201230222132121
5214221121001103
610401111421241
71022626651525
oct154154523631
941435418577
1014524000153
116183468313
122994084821
1314a6048040
149bad18d85
155a013c6bd
hex361b2a799

14524000153 has 4 divisors (see below), whose sum is σ = 15641230948. Its totient is φ = 13406769360.

The previous prime is 14524000151. The next prime is 14524000171. The reversal of 14524000153 is 35100042541.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 8815895449 + 5708104704 = 93893^2 + 75552^2 .

It is a cyclic number.

It is not a de Polignac number, because 14524000153 - 21 = 14524000151 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14524000151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 558615378 + ... + 558615403.

It is an arithmetic number, because the mean of its divisors is an integer number (3910307737).

Almost surely, 214524000153 is an apocalyptic number.

14524000153 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

14524000153 is a deficient number, since it is larger than the sum of its proper divisors (1117230795).

14524000153 is a wasteful number, since it uses less digits than its factorization.

14524000153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1117230794.

The product of its (nonzero) digits is 2400, while the sum is 25.

Adding to 14524000153 its reverse (35100042541), we get a palindrome (49624042694).

The spelling of 14524000153 in words is "fourteen billion, five hundred twenty-four million, one hundred fifty-three", and thus it is an aban number.

Divisors: 1 13 1117230781 14524000153