Base | Representation |
---|---|
bin | 1101001101011011011001… |
… | …0001011001001000000011 |
3 | 1220102111212101201202200121 |
4 | 3103112312101121020003 |
5 | 3400431323131043301 |
6 | 50520220225201111 |
7 | 3026230513511164 |
oct | 323266621311003 |
9 | 56374771652617 |
10 | 14524342440451 |
11 | 469a814727968 |
12 | 1766ab8a90197 |
13 | 81484130842c |
14 | 382da658b76b |
15 | 1a2c28b163a1 |
hex | d35b6459203 |
14524342440451 has 2 divisors, whose sum is σ = 14524342440452. Its totient is φ = 14524342440450.
The previous prime is 14524342440389. The next prime is 14524342440533. The reversal of 14524342440451 is 15404424342541.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14524342440451 - 29 = 14524342439939 is a prime.
It is a super-2 number, since 2×145243424404512 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 14524342440398 and 14524342440407.
It is not a weakly prime, because it can be changed into another prime (14524342440151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7262171220225 + 7262171220226.
It is an arithmetic number, because the mean of its divisors is an integer number (7262171220226).
Almost surely, 214524342440451 is an apocalyptic number.
14524342440451 is a deficient number, since it is larger than the sum of its proper divisors (1).
14524342440451 is an equidigital number, since it uses as much as digits as its factorization.
14524342440451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1228800, while the sum is 43.
Adding to 14524342440451 its reverse (15404424342541), we get a palindrome (29928766782992).
The spelling of 14524342440451 in words is "fourteen trillion, five hundred twenty-four billion, three hundred forty-two million, four hundred forty thousand, four hundred fifty-one".
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