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14530053401 is a prime number
BaseRepresentation
bin11011000100000111…
…10000010100011001
31101111121212012010222
431202003300110121
5214224143202101
610401445245425
71023032262503
oct154203602431
941447765128
1014530053401
1161869221a6
122996103875
1314a7387346
149bba52d73
155a093601b
hex3620f0519

14530053401 has 2 divisors, whose sum is σ = 14530053402. Its totient is φ = 14530053400.

The previous prime is 14530053397. The next prime is 14530053437. The reversal of 14530053401 is 10435003541.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10302453001 + 4227600400 = 101501^2 + 65020^2 .

It is an emirp because it is prime and its reverse (10435003541) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14530053401 - 22 = 14530053397 is a prime.

It is a super-2 number, since 2×145300534012 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14530053481) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7265026700 + 7265026701.

It is an arithmetic number, because the mean of its divisors is an integer number (7265026701).

Almost surely, 214530053401 is an apocalyptic number.

It is an amenable number.

14530053401 is a deficient number, since it is larger than the sum of its proper divisors (1).

14530053401 is an equidigital number, since it uses as much as digits as its factorization.

14530053401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3600, while the sum is 26.

Adding to 14530053401 its reverse (10435003541), we get a palindrome (24965056942).

The spelling of 14530053401 in words is "fourteen billion, five hundred thirty million, fifty-three thousand, four hundred one".