Base | Representation |
---|---|
bin | 1101001101110101010011… |
… | …1110111000000011101110 |
3 | 1220110011211021212001220011 |
4 | 3103131110332320003232 |
5 | 3401040100313143204 |
6 | 50523330452443434 |
7 | 3026565110063350 |
oct | 323352476700356 |
9 | 56404737761804 |
10 | 14531300131054 |
11 | 46a2765103893 |
12 | 176831b01957a |
13 | 8153ac919615 |
14 | 3834666530d0 |
15 | 1a2ed4874304 |
hex | d3754fb80ee |
14531300131054 has 16 divisors (see below), whose sum is σ = 24960721680000. Its totient is φ = 6215219692344.
The previous prime is 14531300131037. The next prime is 14531300131057. The reversal of 14531300131054 is 45013100313541.
It is a super-2 number, since 2×145313001310542 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14531300131057) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1040023084 + ... + 1040037055.
It is an arithmetic number, because the mean of its divisors is an integer number (1560045105000).
Almost surely, 214531300131054 is an apocalyptic number.
14531300131054 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
14531300131054 is a deficient number, since it is larger than the sum of its proper divisors (10429421548946).
14531300131054 is a wasteful number, since it uses less digits than its factorization.
14531300131054 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2080060647.
The product of its (nonzero) digits is 10800, while the sum is 31.
Adding to 14531300131054 its reverse (45013100313541), we get a palindrome (59544400444595).
The spelling of 14531300131054 in words is "fourteen trillion, five hundred thirty-one billion, three hundred million, one hundred thirty-one thousand, fifty-four".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •