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145313132143 = 4771239182201
BaseRepresentation
bin1000011101010101010…
…1100110111001101111
3111220002010021221212011
42013111111212321233
54340100130212033
6150431140422051
713332665146324
oct2072525467157
9456063257764
10145313132143
1156699524a43
12241b50a7927
131091a568a7a
147067120b4b
153ba73ccccd
hex21d5566e6f

145313132143 has 16 divisors (see below), whose sum is σ = 151125626880. Its totient is φ = 139630792000.

The previous prime is 145313132071. The next prime is 145313132147. The reversal of 145313132143 is 341231313541.

It is a cyclic number.

It is not a de Polignac number, because 145313132143 - 29 = 145313131631 is a prime.

It is a super-2 number, since 2×1453131321432 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (145313132147) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 706443 + ... + 888643.

It is an arithmetic number, because the mean of its divisors is an integer number (9445351680).

Almost surely, 2145313132143 is an apocalyptic number.

145313132143 is a deficient number, since it is larger than the sum of its proper divisors (5812494737).

145313132143 is a wasteful number, since it uses less digits than its factorization.

145313132143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 182558.

The product of its digits is 12960, while the sum is 31.

Adding to 145313132143 its reverse (341231313541), we get a palindrome (486544445684).

The spelling of 145313132143 in words is "one hundred forty-five billion, three hundred thirteen million, one hundred thirty-two thousand, one hundred forty-three".

Divisors: 1 47 71 239 3337 11233 16969 182201 797543 8563447 12936271 43546039 608004737 2046663833 3091768769 145313132143