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145313555027 is a prime number
BaseRepresentation
bin1000011101010101011…
…1001110001001010011
3111220002011002102221112
42013111113032021103
54340100232230102
6150431153443535
713333001560244
oct2072527161123
9456064072845
10145313555027
1156699793733
12241b52705ab
131091a6863b4
1470671d0ccb
153ba7463252
hex21d55ce253

145313555027 has 2 divisors, whose sum is σ = 145313555028. Its totient is φ = 145313555026.

The previous prime is 145313554999. The next prime is 145313555041. The reversal of 145313555027 is 720555313541.

145313555027 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 145313555027 - 26 = 145313554963 is a prime.

It is a super-2 number, since 2×1453135550272 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (145313555087) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72656777513 + 72656777514.

It is an arithmetic number, because the mean of its divisors is an integer number (72656777514).

Almost surely, 2145313555027 is an apocalyptic number.

145313555027 is a deficient number, since it is larger than the sum of its proper divisors (1).

145313555027 is an equidigital number, since it uses as much as digits as its factorization.

145313555027 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 315000, while the sum is 41.

Adding to 145313555027 its reverse (720555313541), we get a palindrome (865868868568).

The spelling of 145313555027 in words is "one hundred forty-five billion, three hundred thirteen million, five hundred fifty-five thousand, twenty-seven".