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145320313474178 = 272660156737089
BaseRepresentation
bin100001000010101100000101…
…101010011100110010000010
3201001112111010111200002201222
4201002230011222130302002
5123021412000222133203
61233023121432555042
742416021560456433
oct4102540552346202
9631474114602658
10145320313474178
1142337aa9510897
1214370072b52a82
136311853c15c6b
1427c577d97b48a
1511c01ac909038
hex842b05a9cc82

145320313474178 has 4 divisors (see below), whose sum is σ = 217980470211270. Its totient is φ = 72660156737088.

The previous prime is 145320313474169. The next prime is 145320313474183. The reversal of 145320313474178 is 871474313023541.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 86673251163409 + 58647062310769 = 9309847^2 + 7658137^2 .

It is a super-2 number, since 2×1453203134741782 (a number of 29 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 36330078368543 + ... + 36330078368546.

Almost surely, 2145320313474178 is an apocalyptic number.

145320313474178 is a deficient number, since it is larger than the sum of its proper divisors (72660156737092).

145320313474178 is an equidigital number, since it uses as much as digits as its factorization.

145320313474178 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 72660156737091.

The product of its (nonzero) digits is 6773760, while the sum is 53.

The spelling of 145320313474178 in words is "one hundred forty-five trillion, three hundred twenty billion, three hundred thirteen million, four hundred seventy-four thousand, one hundred seventy-eight".

Divisors: 1 2 72660156737089 145320313474178