1453300068341 has 4 divisors (see below), whose sum is σ = 1585418256384. Its totient is φ = 1321181880300.

The previous prime is 1453300068221. The next prime is 1453300068343. The reversal of 1453300068341 is 1438600033541.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1453300068341 is a prime.

It is a super-2 number, since 2×1453300068341² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1453300068295 and 1453300068304.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1453300068343) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 66059094005 + ... + 66059094026.

It is an arithmetic number, because the mean of its divisors is an integer number (396354564096).

Almost surely, 2^{1453300068341} is an apocalyptic number.

1453300068341 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

1453300068341 is a deficient number, since it is larger than the sum of its proper divisors (132118188043).

1453300068341 is a wasteful number, since it uses less digits than its factorization.

1453300068341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 132118188042.

The product of its (nonzero) digits is 103680, while the sum is 38.

The spelling of 1453300068341 in words is "one trillion, four hundred fifty-three billion, three hundred million, sixty-eight thousand, three hundred forty-one".