Base | Representation |
---|---|
bin | 11011000100100110… |
… | …10011101100000010 |
3 | 1101111220112022210012 |
4 | 31202103103230002 |
5 | 214231214133214 |
6 | 10402112504522 |
7 | 1023112033055 |
oct | 154223235402 |
9 | 41456468705 |
10 | 14534130434 |
11 | 618915734a |
12 | 299754b142 |
13 | 14a8183ca5 |
14 | 9bc3d4a9c |
15 | 5a0e8e03e |
hex | 3624d3b02 |
14534130434 has 4 divisors (see below), whose sum is σ = 21801195654. Its totient is φ = 7267065216.
The previous prime is 14534130431. The next prime is 14534130461. The reversal of 14534130434 is 43403143541.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 43403143541 = 57527 ⋅754483.
It can be written as a sum of positive squares in only one way, i.e., 7980742225 + 6553388209 = 89335^2 + 80953^2 .
It is a super-2 number, since 2×145341304342 (a number of 21 digits) contains 22 as substring.
It is a Curzon number.
It is a self number, because there is not a number n which added to its sum of digits gives 14534130434.
It is not an unprimeable number, because it can be changed into a prime (14534130431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3633532607 + ... + 3633532610.
Almost surely, 214534130434 is an apocalyptic number.
14534130434 is a deficient number, since it is larger than the sum of its proper divisors (7267065220).
14534130434 is an equidigital number, since it uses as much as digits as its factorization.
14534130434 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7267065219.
The product of its (nonzero) digits is 34560, while the sum is 32.
Adding to 14534130434 its reverse (43403143541), we get a palindrome (57937273975).
The spelling of 14534130434 in words is "fourteen billion, five hundred thirty-four million, one hundred thirty thousand, four hundred thirty-four".
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