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145342215433 is a prime number
BaseRepresentation
bin1000011101011100010…
…0100011010100001001
3111220011011000112122001
42013113010203110021
54340130101343213
6150434100031001
713333500306262
oct2072704432411
9456134015561
10145342215433
1156703989718
1224202992461
13109235ac70c
14706ad31969
153ba9c251dd
hex21d7123509

145342215433 has 2 divisors, whose sum is σ = 145342215434. Its totient is φ = 145342215432.

The previous prime is 145342215349. The next prime is 145342215437. The reversal of 145342215433 is 334512243541.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 100379981584 + 44962233849 = 316828^2 + 212043^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-145342215433 is a prime.

It is a super-2 number, since 2×1453422154332 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 145342215392 and 145342215401.

It is not a weakly prime, because it can be changed into another prime (145342215437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72671107716 + 72671107717.

It is an arithmetic number, because the mean of its divisors is an integer number (72671107717).

Almost surely, 2145342215433 is an apocalyptic number.

It is an amenable number.

145342215433 is a deficient number, since it is larger than the sum of its proper divisors (1).

145342215433 is an equidigital number, since it uses as much as digits as its factorization.

145342215433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 172800, while the sum is 37.

Adding to 145342215433 its reverse (334512243541), we get a palindrome (479854458974).

The spelling of 145342215433 in words is "one hundred forty-five billion, three hundred forty-two million, two hundred fifteen thousand, four hundred thirty-three".