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145343554201 is a prime number
BaseRepresentation
bin1000011101011100100…
…1101010001010011001
3111220011020112120002001
42013113021222022121
54340130422213301
6150434144441001
713333514553346
oct2072711521231
9456136476061
10145343554201
115670471353a
1224203319161
131092395aba1
14706b19d7cd
153ba9ddbc01
hex21d726a299

145343554201 has 2 divisors, whose sum is σ = 145343554202. Its totient is φ = 145343554200.

The previous prime is 145343554171. The next prime is 145343554243. The reversal of 145343554201 is 102455343541.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 90072014400 + 55271539801 = 300120^2 + 235099^2 .

It is a cyclic number.

It is not a de Polignac number, because 145343554201 - 223 = 145335165593 is a prime.

It is a super-2 number, since 2×1453435542012 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (145343554001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72671777100 + 72671777101.

It is an arithmetic number, because the mean of its divisors is an integer number (72671777101).

Almost surely, 2145343554201 is an apocalyptic number.

It is an amenable number.

145343554201 is a deficient number, since it is larger than the sum of its proper divisors (1).

145343554201 is an equidigital number, since it uses as much as digits as its factorization.

145343554201 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144000, while the sum is 37.

Adding to 145343554201 its reverse (102455343541), we get a palindrome (247798897742).

The spelling of 145343554201 in words is "one hundred forty-five billion, three hundred forty-three million, five hundred fifty-four thousand, two hundred one".